29=4E-05x^2-0.0345x+36.9

Solution for 29=4E-05x^2-0.0345x+36.9 equation:

29=4-05E^2-0.0345E+36.9

We move all terms to the left:

29-(4-05E^2-0.0345E+36.9)=0

We get rid of parentheses

05E^2+0.0345E-4-36.9+29=0

We add all the numbers together, and all the variables

05E^2+0.0345E-11.9=0

a = 05; b = 0.0345; c = -11.9;
Δ = b2-4ac
Δ = 0.03452-4·05·(-11.9)
Δ = 238.00119025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$E_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$E_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$E_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.0345)-\sqrt{238.00119025}}{2*05}=\frac{-0.0345-\sqrt{238.00119025}}{10}
$
$E_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.0345)+\sqrt{238.00119025}}{2*05}=\frac{-0.0345+\sqrt{238.00119025}}{10}
$